KC Sinha Mathematics Solution Class 9 Chapter 10 Quadrilaterals exercise 10.2

Page 10.34

EXERCISE 10.2


Type 1


QUESTION 1

Fill in the blanks :
(i) In a ΔPQR , M and N are the mid-points of PQ and PR respectively , then MN=__
(ii) In a ΔABC , D and E are the mid-points of AB and AC respectively , if AB=7.4cm , BC=5.4cm and AC=4.4 cm , then length of DE will be __
(iii) In a ΔABC , D and E are the mid-points of the side AB and AC respectively. If DE=2.6 cm , then length of BC will be __
(iv) In a triangle , line joining the mid-points of two sides is parallel and __ of the third side
(v) If a line is divided by the three lines in the ratio 1:3 , then second line will be divided by these three lines in the ratio __
Sol :


QUESTION 2

What is the relation between the line segment joining the mid-points of two sides and the third side of a triangle ?
Sol :



QUESTION 3

Three parallel lines AD , BE and CF are intersected by two transversals at points A, B  , C and D , E , F . If AB=BC=4 cm , then find the value of DE:EF
Sol :


QUESTION 4

Which figure is formed when mid-points of consecutive sides of a quadrilateral are joined ?
Sol :


QUESTION 5

What type of triangle is formed when mid-points of consecutive sides of a equilateral triangle are joined ?
Sol :


QUESTION 6

In ΔDEF , A and B are the mid-points of the sides DE and DF , then what type of quadrilateral ABEF will be found ?
Sol :


TYPE 2

QUESTION 7

ABCD is a trapezium in which AB||CD and P and Q are the mid-points of AD and BC. If AB=4 cm , CD=7 cm , then find PQ
[Hint : Line segment joining the mid-points of non-parallel sides of a trapezium is half of the sum of the parallel sides.]
Sol :


QUESTION 8

In the adjoining f‌igure, ΔABC is an equilateral triangle . On joining the mid-points of the sides of ΔABC , ΔDEF is formed. Again , on joining the mid-points of the sides of the ΔDEF , ΔPQR is formed. If AB=12 cm  , then find the length of sides of the ΔPQR
ABCD is a trapezium in which AB||CD and P and Q are the mid-points of AD and BC. If AB=4 cm , CD=7 cm , then find PQ
Sol :


QUESTION 9

If ABCD is a trapezium in which AB||DC , E is the mid-point of AD and F is the mid-point of BC.
If ABCD is a trapezium in which AB||DC , E is the mid-point of AD and F is the mid-point of BC.
(i) If AB=4 cm and DC=6cm , then find EF
(ii) If AB=8cm and DC=6cm , then find EF
Sol :


QUESTION 10

In a trapezium ABCD , AB||DC and point E is the mid-point of the side AD. a line through the point E and parallel to the side AB meets the line BC in F . Prove that F is the mid-point of BC. [Hint : join AC]
If ABCD is a trapezium in which AB||DC , E is the mid-point of AD and F is the mid-point of BC.
Sol :


TYPE 3

QUESTION 11

In parallelogram ABCD , P and Q are the mid-points of DC and BC respectively. Prove that CR=1/2 AC
[Hint : Join B and D and let BD and AC intersect at O . Now , OC=1/2AC. Now in ΔCBD ,  P and Q are the mid-points of DC and BC respectively
∴ PQ||BD or PR||DO and RQ||OB
Now in ΔOCD , PR||OD
∴ R is the mid-point of OC
Now CR=1/2 OC = 1/2 (1/2AC)=1/4 AC     [∵ OC=1/2 AC]
]
Sol :


QUESTION 12

In ΔABC, M and N are points on AB and AC , such that AM=1/4 AB and AN=1/4 AC . Prove that MN=1/4 BC
[Hint: Let P and Q be the mid-points of AB and AC respectively
∴PQ=1/2 BC
Now , M and N are the mid-points of AP and AQ respectively\
∴MN=1/2 PQ = 1/4 BC]
Sol :


QUESTION 13

ΔABC is an isosceles triangle in which AB=AC. D , E and F are the mid-points of BC , CA and AB respectively . Prove that line segment AD is perpendicular to EF and also, it is bisected by EF
<fig to be added>
[Hint : AB=AC, BD=DC , AD=AD
⇒ ΔABD≅ΔACD [SSS congruence rule]
⇒∠ADB≅∠ADC=90°
⇒ F is the mid-point of AB and E is the mid-point of AC
⇒FE||BC
⇒ ∠AOF≅∠ADC=90° [corresponding angles]
⇒ F is the mid-point of AB and FO||BD
⇒ O is the mid-point of AD
Hence AD⊥EF and AO=OD]
Sol :


QUESTION 14

In f‌igure, three parallel lines l, m and n are intersected by the transversal p at points A , B and C respectively and by the transversal 'q' at D , E and F respectively.
If AB:BC=1:2 , then prove that DE:EF=1:2
<fig to be added>
Sol :


 

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