Exercise 29.2
Question 1
If the lines \frac{x-1}{-3}=\frac{y-2}{2 k}=\frac{z-3}{2} and \quad \frac{x-1}{3 k}=\frac{y-1}{1}=\frac{z-6}{-5} are perpendicular, Find the value of k.
Sol :
Question 2
Show that the line joining the origin to the point (2,1,1) is perpendicular to the line determined by the points (3,5,-1) and (4,3,-1)
Sol :
Question 3
If the coordinates of the points A,B,C,D be (1,2,3),(4,5,7),(-4,3,-6) and (2,9,2) respectively, then find the angle between AB and CD.
Sol :
Question 4
Find the angle between the lines whose direction ratios are a, b, c and b-c, c-a, a-b
Sol :
Question 5
show that the three lines with direction cosines
\frac{12}{13}, -\frac{3}{13},-\frac{4}{13}; \frac{4}{13}, \frac{12}{13}, \frac{3}{13} ; \frac{3}{13},-\frac{4}{13}, \frac{12}{13} are mutually perpendicular.
Sol :
Question 6
Show that the line through the points (4,7,8) and (2,3,4) is parallel to the line through the points (-1,-2,1) and (1,2,5)
Sol :
Question 7
Show that the line through the points (1,-1,2) and (3,4,-2) is perpendicular to the line through the points (0,3,2) and (3,5,6)
Sol :
Question 8
Show that the line \frac{x-5}{7}=\frac{y+2}{-5}=\frac{z}{1} and \frac{x}{1}=\frac{y}{2}=\frac{z}{3} are perpendicular to each other.
Sol :
Question 9
Find the angle between the following pair of lines :
(i) \vec{r}=3 \hat{i}+\hat{j}-2 \hat{k}+\lambda(\hat{i}-\hat{j}-2 \hat{k}) and \vec{r}=2 \hat{i}-\hat{j}-56 \hat{k}+\mu(3 \hat{i}-5 \hat{j}-4 \hat{k})
(ii) \vec{r}=2 \hat{i}-5 \hat{j}+\hat{k}+\lambda(3 \hat{i}+2 \hat{j}+6 \hat{k}) and \vec{r}=7 \hat{\imath}-6 \hat{k}+\mu(\hat{i}+2 \hat{j}+2 \hat{k})
Sol :
Question 10
Find the angle between the following pair of lines :
(i) \frac{x}{2}=\frac{y}{2}=\frac{z}{1} and \frac{x-5}{4}=\frac{y-2}{1}=\frac{z-3}{8}
(ii) \frac{x-2}{2}=\frac{y-1}{5}=\frac{z+3}{-3} and \frac{x+2}{-1}=\frac{y-4}{8}=\frac{z-5}{4}
Sol :
Question 11
Find the value of p so that the lines \frac{1-x}{3}=\frac{7 y-14}{2 p}=\frac{z-3}{2} and \frac{7-7 x}{3 p}=\frac{y-5}{1}=\frac{6-z}{5} are at right angles.
Sol :
Question 12
If l_{1}, m_{1}, n_{1} and l_{2}, m_{2}, n_{2} are the direction cosines of two mutually perpendicular lines, show that the direction cosines of the line perpendicular to both of these are m_{1} n_{2}-m_{2} n_{1}, n_{1}-l_{2}-n_{2} l_{1}, l_{1} m_{2}-l_{2} m_{1} .
Sol :
TYPE-II
Question 13
Find the equation of a line parallel to x-axis and passing through the origin.
Sol :
Question 14
Find the equation of the line which passes through the point (1,2,3) and is parallel to the vector 3 \hat{i}+2 \hat{j}-2 \hat{k}.
Sol :
Question 15
The cartesian equation of a line is \frac{x-5}{3}=\frac{y+4}{7}=\frac{z-6}{2}. Write its vector equation.
Sol :
Question 16
Find the vector and cartesian equation of the line that passes through the origin and (5,-2,3).
Sol :
Question 17
Find the vector equation of the line passing through the points (-1,0,2) and (3,4,6).
Sol :
Question 18
The cartesian equation of a line is \frac{x+3}{2}=\frac{y-5}{4}=\frac{z+6}{2}
Find its vector equation.
Sol :
Question 19
Find the equation of the line in cartesian form that passes through the point with position vector 2 \hat{i}-\hat{j}+4 \hat{k} and is in the direction \hat{i}+2 \hat{j}-\hat{k}.
Sol :
TYPE-III : (Problems on shortest distance between two lines)
Question 20
Find the shortest distance between the following pair of lines :
(i)
\vec{r}=\hat{i}+\hat{j}+\lambda(2 \hat{i}-\hat{j}+\hat{k}) and
\vec{r}=2 \hat{i}+\hat{j}-\hat{k}+\mu(3 \hat{i}-5 \hat{j}+2 \hat{k})
(ii)
\vec{r}=\hat{i}+2 \hat{j}+\hat{k}+\lambda(\hat{i}-\hat{j}+\hat{k}) and
\vec{r}=2 \hat{i}-\hat{j}-\hat{k}+\mu(2 \hat{i}+\hat{j}+2 \hat{k})
(iii)
\vec{r}=(1-t) \hat{i}+(t-2) \hat{j}+(3-2 t) \hat{k}
\vec{r}=(s+1) \hat{i}+(2 s-1) \hat{j}-(2 s+1) \hat{k}
(iv)
\vec{r}=\hat{i}+2 \hat{j}+3 \hat{k}+\lambda(\hat{i}-3 \hat{j}+2 \hat{k}) and
\vec{r}=4 \hat{i}+5 \hat{j}+6 \hat{k}+\mu(2 \hat{i}+3 \hat{j}+\hat{k})
(v)
\vec{r}=\hat{i}+2 \hat{j}-4 \hat{k}+\lambda(2 \hat{i}+3 \hat{j}+6 \hat{k}) and
\vec{r}=3 \hat{i}+3 \hat{j}-5 \hat{k}+\mu(2 \hat{i}+3 \hat{j}+6 \hat{k})
Question 21
Find the shortest distance between the following pair of lines :
\frac{x+1}{7}=\frac{y+1}{-6}=\frac{z+1}{1} and \frac{x-3}{1}=\frac{y-5}{-2}=\frac{z-7}{1}
Sol :
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